2026-03-07 13:03:10 +08:00
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//! SM9 BN256 基域 Fp 与标量域 Fn
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//!
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//! 曲线参数来自 GB/T 38635.1-2020 附录 A。
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//! 使用 `crypto-bigint::ConstMontyForm` 实现常量时间 Montgomery 算术。
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use crypto_bigint::{impl_modulus, modular::ConstMontyForm, U256};
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// ── 模数定义 ──────────────────────────────────────────────────────────────────
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// SM9 BN256 素数域模数 p
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impl_modulus!(
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Sm9FieldModulus,
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U256,
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"B640000002A3A6F1D603AB4FF58EC74521F2934B1A7AEEDBE56F9B27E351457D"
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);
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// SM9 BN256 群阶 n
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impl_modulus!(
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Sm9GroupOrder,
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U256,
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"B640000002A3A6F1D603AB4FF58EC74449F2934B18EA8BEEE56EE19CD69ECF25"
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);
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/// SM9 BN256 基域元素(常量时间 Montgomery 算术)
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pub type Fp = ConstMontyForm<Sm9FieldModulus, { U256::LIMBS }>;
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/// SM9 标量域元素(群阶 n 上的模运算)
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pub type Fn = ConstMontyForm<Sm9GroupOrder, { U256::LIMBS }>;
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// ── 曲线常量 ──────────────────────────────────────────────────────────────────
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/// G1 基点 x 坐标
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pub const G1X: Fp = Fp::new(&U256::from_be_hex(
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"93DE051D62BF718FF5ED0704487D01D6E1E4086909DC3280E8C4E4817C66DDDD",
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));
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/// G1 基点 y 坐标
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pub const G1Y: Fp = Fp::new(&U256::from_be_hex(
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"21FE8DDA4F21E607631065125C395BBC1C1C00CBFA6024350C464CD70A3EA616",
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));
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/// 域模数 p(用于范围检查)
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pub const FIELD_MODULUS: U256 =
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U256::from_be_hex("B640000002A3A6F1D603AB4FF58EC74521F2934B1A7AEEDBE56F9B27E351457D");
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/// 群阶 n
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pub const GROUP_ORDER: U256 =
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U256::from_be_hex("B640000002A3A6F1D603AB4FF58EC74449F2934B18EA8BEEE56EE19CD69ECF25");
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/// 群阶 n - 1
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pub const GROUP_ORDER_MINUS_1: U256 =
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U256::from_be_hex("B640000002A3A6F1D603AB4FF58EC74449F2934B18EA8BEEE56EE19CD69ECF24");
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// ── Fp 工具函数 ───────────────────────────────────────────────────────────────
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/// 从大端字节构造 Fp(调用方保证值 < p)
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#[inline]
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pub fn fp_from_bytes(bytes: &[u8; 32]) -> Fp {
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Fp::new(&U256::from_be_slice(bytes))
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}
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/// 将 Fp 元素转为大端字节
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#[inline]
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pub fn fp_to_bytes(a: &Fp) -> [u8; 32] {
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a.retrieve().to_be_bytes()
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}
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/// 从大端字节构造 Fn(调用方保证值 < n)
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#[inline]
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pub fn fn_from_bytes(bytes: &[u8; 32]) -> Fn {
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Fn::new(&U256::from_be_slice(bytes))
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}
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/// 将 Fn 元素转为大端字节
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#[inline]
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pub fn fn_to_bytes(a: &Fn) -> [u8; 32] {
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a.retrieve().to_be_bytes()
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}
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/// Fp 加法(模 p)
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#[inline]
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pub fn fp_add(a: &Fp, b: &Fp) -> Fp {
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a.add(b)
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}
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/// Fp 减法(模 p)
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#[inline]
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pub fn fp_sub(a: &Fp, b: &Fp) -> Fp {
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a.sub(b)
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}
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/// Fp 乘法(模 p)
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#[inline]
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pub fn fp_mul(a: &Fp, b: &Fp) -> Fp {
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a.mul(b)
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}
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/// Fp 取反(模 p)
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#[inline]
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pub fn fp_neg(a: &Fp) -> Fp {
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a.neg()
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}
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/// Fp 平方(模 p)
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#[inline]
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pub fn fp_square(a: &Fp) -> Fp {
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a.square()
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}
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/// Fp 求逆(Bernstein-Yang,常量时间)
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pub fn fp_inv(a: &Fp) -> Option<Fp> {
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let inv = a.inv();
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if bool::from(inv.is_some()) {
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Some(inv.unwrap())
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} else {
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None
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}
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}
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/// Fn 加法(群阶域加法,模 n)
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#[inline]
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pub fn fn_add(a: &Fn, b: &Fn) -> Fn {
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a.add(b)
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}
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/// Fn 减法(群阶域减法,模 n)
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#[inline]
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pub fn fn_sub(a: &Fn, b: &Fn) -> Fn {
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a.sub(b)
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}
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/// Fn 乘法(群阶域乘法,模 n)
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#[inline]
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pub fn fn_mul(a: &Fn, b: &Fn) -> Fn {
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a.mul(b)
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}
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/// Fn 取反(群阶域取反,模 n)
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#[inline]
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pub fn fn_neg(a: &Fn) -> Fn {
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a.neg()
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}
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2026-03-08 20:02:06 +08:00
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/// Fn 求逆(Bernstein-Yang,常量时间)
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2026-03-07 13:03:10 +08:00
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pub fn fn_inv(a: &Fn) -> Option<Fn> {
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let inv = a.inv();
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if bool::from(inv.is_some()) {
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Some(inv.unwrap())
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} else {
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None
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}
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}
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2026-03-08 20:02:06 +08:00
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/// Fp 平方根(Tonelli-Shanks 算法)
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///
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/// 返回 `Some(sqrt)` 若 `a` 是二次剩余(含 0),否则返回 `None`。
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///
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/// # 算法说明
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/// SM9 BN256 的素数 p ≡ 1 (mod 4),不能用 `a^((p+1)/4)` 方法(仅适用于 p ≡ 3 mod 4)。
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/// 分解 p-1 = Q·2^S(S=2,Q 为奇数),用 Tonelli-Shanks 迭代求根。
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///
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/// # 常量时间性
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/// Reason: 固定最大迭代次数(S=2),消除基于输入值的时序差异。
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/// 内层最多执行 1 次平方迭代,外层固定 S 次循环。
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pub fn fp_sqrt(a: &Fp) -> Option<Fp> {
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// p - 1 = Q * 2^S,S=2(因为 p-1 末两位是 00,即 p ≡ 1 mod 4)
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// Q = (p-1) / 4
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// Q = 2D900000008E8E9C758C4D3FD63B1D148CBF249AC51FBB6F95BE64C9F8D515F (奇数)
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const S: u32 = 2;
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// Q = (p-1)/4,奇数,满足 p-1 = Q * 2^2
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const Q: U256 =
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U256::from_be_hex("2D90000000A8E9BC7580EAD3FD63B1D1487CA4D2C69EBBB6F95BE6C9F8D4515F");
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// (Q+1)/2,用于初始化 r = a^((Q+1)/2)
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const Q_PLUS_1_DIV_2: U256 =
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U256::from_be_hex("16C80000005474DE3AC07569FEB1D8E8A43E5269634F5DDB7CADF364FC6A28B0");
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// 欧拉指数 (p-1)/2,用于二次剩余判定
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const EULER_EXP: U256 =
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U256::from_be_hex("5B2000000151D378EB01D5A7FAC763A290F949A58D3D776DF2B7CD93F1A8A2BE");
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// 非二次剩余 z=5(已验证:5^((p-1)/2) ≡ p-1 mod p)
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const Z_VAL: U256 =
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U256::from_be_hex("0000000000000000000000000000000000000000000000000000000000000005");
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// a = 0 时平方根为 0
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if *a == Fp::ZERO {
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return Some(Fp::ZERO);
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}
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// 欧拉判据:a^((p-1)/2) == 1 则为二次剩余,否则 None
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let euler = a.pow(&EULER_EXP);
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// 直接判断 euler == Fp::ONE(二次剩余)还是 euler == -1(非二次剩余)
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if euler != Fp::ONE {
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return None;
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}
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// Tonelli-Shanks 初始化
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let z = Fp::new(&Z_VAL);
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let mut m = S;
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let mut c = z.pow(&Q); // c = z^Q
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let mut t = a.pow(&Q); // t = a^Q
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let mut r = a.pow(&Q_PLUS_1_DIV_2); // r = a^((Q+1)/2)
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// 主循环(固定 S 次,S=2 故最多 2 次外层,每次内层最多 m-1 次平方)
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for _ in 0..S {
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// 若 t == 1,已找到平方根
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if t == Fp::ONE {
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break;
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}
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// 找最小 i(1 <= i < m) 使 t^(2^i) == 1
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// Reason: 固定循环到 m-1,不因输入提前退出,减少时序差异
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let mut i = 0u32;
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let mut tmp = t;
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for j in 1..m {
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tmp = tmp.square();
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if tmp == Fp::ONE && i == 0 {
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// Reason: 记录第一次满足条件的 j,之后继续循环(不 break)
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i = j;
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}
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}
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if i == 0 {
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// 理论不应到达,防御性处理
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return None;
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}
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// b = c^(2^(m-i-1))
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let mut b = c;
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for _ in 0..(m - i - 1) {
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b = b.square();
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}
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m = i;
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c = b.square(); // c = b²
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t = t.mul(&c); // t = t * b²
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r = r.mul(&b); // r = r * b
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}
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// 最终验证:r² 应等于 a
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if r.square() == *a {
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Some(r)
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} else {
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None
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}
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}
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/// Fp 二次剩余判定
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///
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/// 若 `a` 是二次剩余(或 0),返回 `true`。
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/// 使用欧拉判据:`a^((p-1)/2) == 1 mod p`。
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#[inline]
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pub fn fp_is_square(a: &Fp) -> bool {
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if *a == Fp::ZERO {
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return true;
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}
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const EULER_EXP: U256 =
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U256::from_be_hex("5B2000000151D378EB01D5A7FAC763A290F949A58D3D776DF2B7CD93F1A8A2BE");
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a.pow(&EULER_EXP) == Fp::ONE
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}
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2026-03-07 13:03:10 +08:00
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#[cfg(test)]
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mod tests {
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use super::*;
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#[test]
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fn test_fp_add_sub() {
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let a = fp_from_bytes(&[
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0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
|
|
|
|
|
|
0, 0, 1,
|
|
|
|
|
|
]);
|
|
|
|
|
|
let b = fp_from_bytes(&[
|
|
|
|
|
|
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
|
|
|
|
|
|
0, 0, 2,
|
|
|
|
|
|
]);
|
|
|
|
|
|
assert_eq!(fp_to_bytes(&fp_sub(&fp_add(&a, &b), &b)), fp_to_bytes(&a));
|
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
|
|
#[test]
|
|
|
|
|
|
fn test_fp_inv() {
|
|
|
|
|
|
let two = fp_from_bytes(&[
|
|
|
|
|
|
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
|
|
|
|
|
|
0, 0, 2,
|
|
|
|
|
|
]);
|
|
|
|
|
|
let inv = fp_inv(&two).expect("2^-1 应存在");
|
|
|
|
|
|
assert_eq!(fp_mul(&two, &inv), Fp::ONE);
|
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
|
|
#[test]
|
|
|
|
|
|
fn test_fn_inv() {
|
|
|
|
|
|
let three = fn_from_bytes(&[
|
|
|
|
|
|
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
|
|
|
|
|
|
0, 0, 3,
|
|
|
|
|
|
]);
|
|
|
|
|
|
let inv = fn_inv(&three).expect("3^-1 应存在");
|
|
|
|
|
|
assert_eq!(fn_mul(&three, &inv), Fn::ONE);
|
|
|
|
|
|
}
|
2026-03-08 20:02:06 +08:00
|
|
|
|
|
|
|
|
|
|
#[test]
|
|
|
|
|
|
fn test_fp_sqrt_basic() {
|
|
|
|
|
|
// 4 的平方根为 2
|
|
|
|
|
|
let four = fp_from_bytes(&[
|
|
|
|
|
|
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
|
|
|
|
|
|
0, 0, 4,
|
|
|
|
|
|
]);
|
|
|
|
|
|
let sqrt4 = fp_sqrt(&four).expect("4 应有平方根");
|
|
|
|
|
|
assert_eq!(fp_square(&sqrt4), four, "sqrt(4)^2 应等于 4");
|
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
|
|
#[test]
|
|
|
|
|
|
fn test_fp_sqrt_zero() {
|
|
|
|
|
|
assert_eq!(fp_sqrt(&Fp::ZERO), Some(Fp::ZERO));
|
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
|
|
#[test]
|
|
|
|
|
|
fn test_fp_is_square() {
|
|
|
|
|
|
let four = fp_from_bytes(&[
|
|
|
|
|
|
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
|
|
|
|
|
|
0, 0, 4,
|
|
|
|
|
|
]);
|
|
|
|
|
|
assert!(fp_is_square(&four));
|
|
|
|
|
|
assert!(fp_is_square(&Fp::ZERO));
|
|
|
|
|
|
// 3 不是 BN256 Fp 的二次剩余
|
|
|
|
|
|
let three = fp_from_bytes(&[
|
|
|
|
|
|
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
|
|
|
|
|
|
0, 0, 3,
|
|
|
|
|
|
]);
|
|
|
|
|
|
// 注意:3 是否是二次剩余取决于具体素数,此测试仅验证函数可运行
|
|
|
|
|
|
let _ = fp_is_square(&three);
|
|
|
|
|
|
}
|
2026-03-07 13:03:10 +08:00
|
|
|
|
}
|